C Programming Interview Question and Answer SET 5
81.
main()
{
show();
}
void show()
{
printf("I'm the greatest");
}
show();
}
void show()
{
printf("I'm the greatest");
}
Answer:
Compier error: Type mismatch in redeclaration of show.
Explanation:
When the compiler sees the function show it doesn't know anything about it. So
the default return type (ie, int) is assumed. But when compiler sees the actual
definition of show mismatch occurs since it is declared as void. Hence the
error.
The
solutions are as follows:
1. declare void show() in main() .
2. define show() before main().
3. declare extern void show() before the use of show().
1. declare void show() in main() .
2. define show() before main().
3. declare extern void show() before the use of show().
82.
main( )
{
int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf(“%u %u %u %d \n”,a,*a,**a,***a);
printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1);
}
{
int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf(“%u %u %u %d \n”,a,*a,**a,***a);
printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1);
}
Answer:
100,
100, 100, 2
114, 104, 102, 3
114, 104, 102, 3
Explanation:
The given array is a 3-D one. It can also be viewed as a 1-D array.
2
|
4
|
7
|
8
|
3
|
4
|
2
|
2
|
2
|
3
|
3
|
4
|
100
102 104 106 108 110 112 114 116 118 120
122
thus,
for the first printf statement a, *a, **a give address of first element. since
the indirection ***a gives the value. Hence, the first line of the output.
for
the second printf a+1 increases in the third dimension thus points to value at
114, *a+1 increments in second dimension thus points to 104, **a +1 increments
the first dimension thus points to 102 and ***a+1 first gets the value at first
location and then increments it by 1. Hence, the output.
83.
main( )
{
int a[ ] = {10,20,30,40,50},j,*p;
for(j=0; j<5; j++)
{
printf(“%d” ,*a);
a++;
}
p = a;
for(j=0; j<5; j++)
{
printf(“%d ” ,*p);
p++;
}
}
int a[ ] = {10,20,30,40,50},j,*p;
for(j=0; j<5; j++)
{
printf(“%d” ,*a);
a++;
}
p = a;
for(j=0; j<5; j++)
{
printf(“%d ” ,*p);
p++;
}
}
Answer:
Compiler error: lvalue required.
Explanation:
Error is in line with statement a++. The operand must be an lvalue and may be
of any of scalar type for the any operator, array name only when subscripted is
an lvalue. Simply array name is a non modifiable lvalue.
84.
main( )
{
static int a[ ] = {0,1,2,3,4};
int *p[ ] = {a,a+1,a+2,a+3,a+4};
int **ptr = p;
ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*++ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
++*ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
}
{
static int a[ ] = {0,1,2,3,4};
int *p[ ] = {a,a+1,a+2,a+3,a+4};
int **ptr = p;
ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*++ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
++*ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
}
Answer:
111
222
333
344
222
333
344
Explanation:
Let us consider the array and the two pointers with some address
a
0
|
1
|
2
|
3
|
4
|
100
102 104 106 108
p
100
|
102
|
104
|
106
|
108
|
1000
1002 1004 1006 1008
ptr
1000
|
2000
After
execution of the instruction ptr++ value in ptr becomes 1002, if scaling factor
for integer is 2 bytes. Now ptr – p is value in ptr –starting location of array
p, (1002 – 1000) / (scaling factor) = 1,
*ptr
– a = value at address pointed by ptr – starting value of array a, 1002 has a
value 102 so the value is (102 – 100)/(scaling factor) = 1, **ptr is the value
stored in the location pointed by the pointer of ptr = value pointed by value
pointed by 1002 = value pointed by 102 = 1. Hence the output of the firs printf
is 1, 1, 1.
After
execution of *ptr++ increments value of the value in ptr by scaling factor, so
it becomes1004. Hence, the outputs for the second printf are ptr – p = 2, *ptr
– a = 2, **ptr = 2.
After
execution of *++ptr increments value of the value in ptr by scaling factor, so
it becomes1004. Hence, the outputs for the third printf are ptr – p = 3, *ptr –
a = 3, **ptr = 3.
After
execution of ++*ptr value in ptr remains the same, the value pointed by the
value is incremented by the scaling factor. So the value in array p at location
1006 changes from 106 10 108,. Hence, the outputs for the fourth printf are ptr
– p = 1006 – 1000 = 3, *ptr – a = 108 – 100 = 4, **ptr = 4.
85.
What is dangling pointer in c?
If any pointer is pointing the memory address of any variable but after some variable has deleted from that memory location while pointer is still pointing such memory location. Such pointer is known as dangling pointer and this problem is known as dangling pointer problem.
If any pointer is pointing the memory address of any variable but after some variable has deleted from that memory location while pointer is still pointing such memory location. Such pointer is known as dangling pointer and this problem is known as dangling pointer problem.
86.
What are merits and demerits of array in c?
Merits:
(a) We can easily access each element of array.
(b) Not necessity to declare too many variables.
(c) Array elements are stored in continuous memory location.
Merits:
(a) We can easily access each element of array.
(b) Not necessity to declare too many variables.
(c) Array elements are stored in continuous memory location.
Demerits:
(a) Wastage of memory space. We cannot change size of array at the run time.
(b) It can store only similar type of data
(a) Wastage of memory space. We cannot change size of array at the run time.
(b) It can store only similar type of data
87.
Where are the auto variables stored?
Auto
variables are stored in main memory and their default value is a garbage value.
88.
Why Preincrement operator is faster than Postincrement?
Evaluation
of any expression is from left to right. Preincrement is faster because it
doesn't need to save the current value for next instruction whereas
Postincrement needs to saves current value to be incremented after execution of
current instruction.
89.
Difference between arrays and linked list?
Major
differences between arrays and linked lists are: (i) In array consecutive
elements are stored in consecutive memory locations whereas in linked list it
not so. (ii) In array address of next element is consecutive and whereas
in linked list it is specified in the address part of each node.(iii) Linked
List makes better use of memory than arrays.(iv) Insertion or deletion of an
element in array is difficult than insertion or deletion in linked list
90.
What is the use of typedef?
(i)It
increases the portability.
(ii) It simplify the complex declaration and improve readability of the program.
(ii) It simplify the complex declaration and improve readability of the program.
91.
What are library Functions?
Library
Functions are predefined functions and stored in .lib files.
92.
What is a structure?
Structure
is a collection of heterogeneous (i.e. related data items which can be of
different types) held together to a single unit. The data items enclosed within
a structure are called its members which may be of data type int, float, char,
array etc.
93.
What is a pointer?
Pointer
is a variable that contains address of another variable in the memory. Pointers
are quite useful in creation of linked data structures (such as linked lst,
trees graphs), managing object allocated memory dynamically, optimize the
program to execute faster and use less memory.
94.
What are the techniques you use for debugging?
(i)Using
compiler’s features
(ii)Read The Fine Module
(iii)printf( ) debugging
(iv)Code grinding
(v)Assertion
(ii)Read The Fine Module
(iii)printf( ) debugging
(iv)Code grinding
(v)Assertion
95.
What are macros? What are its advantages and disadvantages?
Macro
is a Pre-processor.Major advantage of using the macro is to increase the speed
of the execution of the program.
Major disadvantage of the macros are:
(i) No type checking is performed in macro. This may cause error.
(ii) A macro call may cause unexpected results.
Major disadvantage of the macros are:
(i) No type checking is performed in macro. This may cause error.
(ii) A macro call may cause unexpected results.
96.
What is difference between Structure and Unions?
(i)
In structure every member has its own memory whereas in union its members share
the same member space.
(ii) In structure, it is possible to initialize all the members at the same time which is not possible in case of union.
(iii) A structure requires more space than union(for the same type of members).
(iv) In union different interpretations of the same memory space are possible which is not so in case of structures.
(ii) In structure, it is possible to initialize all the members at the same time which is not possible in case of union.
(iii) A structure requires more space than union(for the same type of members).
(iv) In union different interpretations of the same memory space are possible which is not so in case of structures.
97.
What are the advantages of using Unions?
(i)
Efficient use of memory as it it does not demand memory space for its all
members rather it require memory space for its largest member only.
(ii) Same memory space can be interpreted differently for different members of the union.
(ii) Same memory space can be interpreted differently for different members of the union.
98.
What is the difference between ordinary variable and pointer in C?
An
ordinary variable is like a container it can hold any value and we can change
the value of ordinary variable at a time throughout the program .A pointer is a
variable that stores the address of another Variable.
99.
What are segment and offset addresses?
When paging technique is performed, the page will breaks into segments and its sequence is said to be segments and its width can be said as offset. In short,segment is a physical address and offset is logical address.
When paging technique is performed, the page will breaks into segments and its sequence is said to be segments and its width can be said as offset. In short,segment is a physical address and offset is logical address.
100.
When should a type cast be used?
There
are two situations in which to use a type cast. The first use is to change the
type of an operand to an arithmetic operation so that the operation will be
performed properly.
The second case is to cast pointer types to and from void * in order to interface with functions that expect or return void pointers. For example, the following line type casts the return value of the call to malloc() to be a pointer to a foo structure.
struct foo *p = (struct foo *) malloc(sizeof(struct foo));
The second case is to cast pointer types to and from void * in order to interface with functions that expect or return void pointers. For example, the following line type casts the return value of the call to malloc() to be a pointer to a foo structure.
struct foo *p = (struct foo *) malloc(sizeof(struct foo));
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