Q.No. :
|
1
|
Question :
|
Sameer can do a piece of work in
9hours. Rahul can do the same piece of work in 8hours. Their boss asks them
to work along with Ronak and hence they finish the work in 3 hours. If
their boss offers them Rs. 7200 for the work, how much does Ronak earn?
Report
| Discuss
|
A:
|
Rs
6900
|
 B (Your Answer):
|
Rs
5000
|
C:
|
Rs
4200
|
 D:
|
Rs
2100
|
Answer: D
|
|
|
Part of the work done by ronak =
1/3-(1/8 + 1/9)
1/x = 7/72
Amount that ronak gets = 7200(7/72)* 3= Rs 2100.
|
|
Q.No. :
|
2
|
Question :
|
Abhishek was given a piece of
work to be done in 24 days. The lazy person that he was, he works at 75%,
50%, 80% and 25% of his usual rate on 1st, 2nd, 3rdand
4th days respectively. In how many days will he finish the
remaning jo. If he works at his usual rate from the 5th day?
Report
| Discuss
|
A:
|
21.7
|
B (Your Answer):
|
24
|
C:
|
25
|
D:
|
26.5
|
Answer: A
|
|
|
At his usual pace Abhishek can
do 1/24 of the work in one day.
Work done on the first day = (3/4)(1/24)=1/32
second day= 1/48
third day = 1/30
fourth day = 1/96.
Work left = 1-[1/32+1/48+1/30+1/96] = 217/240
Time taken to complete remaining work= (217/240)* 24 = 21.7 days
|
|
Q.No. :
|
3
|
Question :
|
An empty conical water container
is placed on its base and water is poured into it through the vertex. It
takes 20 minutes for the water level to rise to 40% of the height of the
cone. How long will it take for the water level to rise to 70% of the
height of the cone?
Report
| Discuss
|
A (Your Answer):
|
22.8
minutes
|
B:
|
24.8
minutes
|
C:
|
35
minutes
|
D:
|
40
minutes
|
Answer: B
|
|
|
When water level rise upto 40 %.
Vol of water =1/3 πR2H-1/3πr2h
h = H-H*40/100
= 3/5H
r = 3/5R ( from triangle law of geometry)
So vol of water poured in 20 min = 1/3 π[R2H-(3/5R)2(3/5H)]
= 1/3 π[98/125R2H]
Now to raise the water to 70 %
h1 = H-H*70/100
= 3/10H
r1 = 3/10R
Vol of water will be = 1/3 π[R2H-(3/10R)2(3/10H)]
= 1/3 π[973/1000R2H]
Required time =( 973/1000)*(20)/(98/125)
= 24.8 min Ans
|
|
Q.No. :
|
4
|
Question :
|
Two alloy A and B contains
copper and zinc in the ratio 5:11 and 3:5 respectively. If equal weights of
the two alloy are melted together to form a third alloy, find the ratio of
the weights of copper and zinc in the third alloy.
Report
| Discuss
|
 A (Your Answer):
|
11:21
|
B:
|
9:19
|
C:
|
21:11
|
D:
|
19:9
|
Answer: A
|
|
|
Q.No. :
|
5
|
Question :
|
There are two classes A and B.
The average weight of the students in class A is 40 kg. The average weight
of the students in class B is 60kg. A student, whose weight is xkg left A
and joined B. As a result, the average weight of A, as well as that of decreased,
which of the following must be true?
Report
| Discuss
|
A:
|
35
< x <= 40
|
B:
|
40
< x <60
|
C (Your Answer):
|
60
<= x <65
|
D:
|
30
< x <= 35
|
Answer: B
|
|
|
Q.No. :
|
6
|
Question :
|
Vipin plays a game wherein he
tosses a coin and scores 7 points if head comes up and 8 points for a tail.
If an exact total 167 points is required to win the game, then in how much
ways can Vipin win?
Report
| Discuss
|
A:
|
2
|
B:
|
3
|
C (Your Answer):
|
4
|
D:
|
5
|
Answer: B
|
|
|
Let head and tail occur x and y
times respectively.
So, for Vipin to win,
7x + 8y = 167
Possible value of x and y is
x=1, y=20
x=9, y=13
x=17, y=6
Total number of ways = 3
|
|
Q.No. :
|
7
|
Question :
|
|
A:
|
1
|
B (Your Answer):
|
2
|
C:
|
3
|
D:
|
Root(5)
|
Answer: B
|
|
|
60a=3
So, a = log603
60b=5
So, b = log605
Now,
Let Y = 12[1-a-b]/[2(1-b)]
Taking log with base 60 on both sides,
log60Y=log6012[1-a-b]/[2(1-b)]
Or, log60Y=[1-a-b]/[2(1-b)] log6012
(1-a-b)/2(1-b) = (1- log603 - log605)/2(1 - log605)
= ( log6060 - log603 - log605)/2(log6060
- log605)
= [log60(60/15)]/2[log60(60/5)]
= log604/2log6012
log60Y = (log604/2log6012)* log6012
= 1/2log604
=log602
So, Y = 2 Ans
|
|
Q.No. :
|
8
|
Question :
|
In a race of length D m , A
beats B by X m and C by Y m. By what distance does B beat C in the same
race?
Report
| Discuss
|
A:
|
(Y-X)D
/ (D-Y) m
|
B (Your Answer):
|
(Y-X)D
/ (D-X) m
|
C:
|
(D-Y)D
/ (D-X) m
|
D:
|
(D-X)D
/ (D-Y) m
|
Answer: B
|
|
|
Suppose time taken by A, B and C
to finish the race are t1, t2, t3 respectively.
So Speed of A, B and C are D/t1, D/t2 and D/t3
Now When A finishes the race distance travelled by B = Dt2/t1
and distance travelled by C = Dt3/t1
According to question, D-Dt2/t1 = X ............(i)
and D-Dt3/t1 = Y ............(ii)
We have to find D-Dt3/t2
from (i) t2/t1 = (D-X)/D ..... (iii)
from (ii) t3/t1 = (D-Y)/D ..... (iv)
From (iii) and (i) we get t3/t2 = (D-Y)/(D-X)
So, D-Dt3/t2
= D[(1-(D-Y)/(D-X)]
= D(Y-X)/(D-X)
Hence B
|
|
Q.No. :
|
9
|
Question :
|
A and B are two stations. Train
P started from A towards B at 6:00 a.m at 90 kmph. At the same time, train
Q started from C, an intermediate station 60 km from A, and travelled
towards B at 60 kmph, Train R started from B towards A at 7:00 a.m at 120
kmph. All the trains crossed each other simultaneously. Find AB(in km).
Report
| Discuss
|
A (Your Answer):
|
390
|
B:
|
360
|
C:
|
330
|
D:
|
300
|
Answer: D
|
|
|
Q.No. :
|
10
|
Question :
|
A, B, C are running around a
circular park. They start at the same point. A overtakes C, 3 times for
every round that C makes. C overtakes B, 6 times for every round that B
makes. What is the ratio of A's speed to that of B?
Report
| Discuss
|
A:
|
9:2
|
B:
|
18:1
|
C (Your Answer):
|
28:1
|
D:
|
21:1
|
Answer: C
|
|
|
As A overtakes C three times ,
A's speed must be four times of C
and C speed is 7 times more than B
A=4C
B=C/7
therefore
A/B=28:1
|
|
Q.No. :
|
11
|
Question :
|
There are 4 identical oranges, 3
identical mangoes and 2 identical apples in the basket. the number of ways
in which we can select one or more fruits from the basket is
Report
| Discuss
|
A:
|
60
|
B:
|
59
|
C (Your Answer):
|
57
|
D:
|
56
|
Answer: B
|
|
|
There are 4 oranges, 3 mangoes
and 2 apples.
From 4 oranges we can select either no orange or 1 oranges or 2 or 3 or all
4 oranges.
So No of ways of chosing = 5
Similarly we can chose 0, 1, 2 or 3 mangoes out of 3 mangoes.
and we can chose 0, 1 or all 2 apples out of 2 apples.
So total number of ways of selecting fruit = 5*4*3 = 60
But we have to exclude on case in which no fruit is chosen
Hence required answer = 60 - 1 = 59
|
|
Q.No. :
|
12
|
Question :
|
P is an integer whose digits are
zeroes and ones. The sum of the digits of P is 4 and 105< P
<107. How many values P can take?
Report
| Discuss
|
A:
|
60
|
B (Your Answer):
|
10
|
C:
|
20
|
D:
|
30
|
Answer: D
|
|
|
Q.No. :
|
13
|
Question :
|
A question paper consists of 5
problems, each problem having 3 internal choices. In how many ways can a
candidate attempt one or more problems?
Report
| Discuss
|
A (Your Answer):
|
63
|
B:
|
511
|
C:
|
1023
|
D:
|
31
|
Answer: C
|
|
|
There are 5 problems. Each problem having three choices
to answer. (Suppose the question as a multiple choice question having 3
options)
So a candidate can either answer 1, 2, 3, 4 or all 5 questions.
No of ways to answer only one question = 5C1*3
No of ways to answer 2 questions = 5C2*32
(For each question there are 3 different choices to answer)
No of ways to answer 3 questions = 5C3*33
No of ways to answer 4 questions = 5C4*34
No of ways to answer 5 questions = 5C5*35
So, Total number of ways = 5C1*3 + 5C2*32
+ 5C3*33 + 5C4*34
+ 5C5*35
= (1+3)5 - 1(From binomial theorem)
=1023
|
|
Q.No. :
|
14
|
Question :
|
Three men shot the same target.
The probability of the first, second and the third man hitting the target
respectively is 0.3, 0.5 and 0.6. Find the probability that exactly one of
them hits the target.
Report
| Discuss
|
A:
|
0.41
|
B (Your Answer):
|
0.6
|
C:
|
0.5
|
D:
|
0.7
|
Answer: A
|
|
|
Q.No. :
|
15
|
Question :
|
There are 3 urns containing 3 white
and 4 green balls; 2 white and 4 green balls; 1 white and 1 green ball. One
urn is chosen at random and a ball is drawn from it. What is the
probability that it is a green ball?
Report
| Discuss
|
A:
|
43/126
|
B:
|
4/21
|
C:
|
7/12
|
D (Your Answer):
|
73/126
|
Answer: D
|
|
|
Q.No. :
|
16
|
Question :
|
Find the next element in the
series given below :-
7, 25, 61, 121, ___
Report
| Discuss
|
A (Your Answer):
|
181
|
B:
|
201
|
C:
|
211
|
D:
|
251
|
Answer: C
|
|
|
Series is :-23-1, 33-2,
43-3, 53-4, ........
|
|
Q.No. :
|
17
|
Question :
|
P,Q,R,S,T and U are six players
from whom two captains X and Y wish to form two teams of 3 players each. P
and Q must be in different teams. S and T must be in the same team. If X
has P and U in his team, then Y must have taken a team of
Report
| Discuss
|
A:
|
Q,S,T
|
B (Your Answer):
|
P,S,T
|
C:
|
R,S,T
|
D:
|
P,R,T
|
Answer: A
|
|
|
Q.No. :
|
18
|
Question :
|
A message can be sent from one
transmitter to another among 9 transmitters A,B,C,D,E,F,G,H and , as shown
below.
From A to B, from B to C, from C to D, from B to E, from D to H, from E to
F, from E to H, from G to H, from F to G, from H to I, from G to I and from
D to I.
In how many ways can a message be sent from A to I?
Report
| Discuss
|
A:
|
7
|
B (Your Answer):
|
6
|
C:
|
5
|
D:
|
4
|
Answer: C
|
|
|
The
following two questions are based on the information given below:- The
following is the conversation between A, B and C each of whom has different
surname among P, Q and R. One of them is lying and two are telling truth.
A :- I am not a Q. C is a P. B is not a R.
B:- I am a R. A is a P. C is a Q.
C:- I am not Q. A is not a P. B is a Q.
|
Q.No. :
|
19
|
Question :
|
|
A (Your Answer):
|
A
|
B:
|
C
|
C:
|
B
|
D:
|
Either
A or B
|
Answer: A
|
|
|
Consider all 3 cases:
Case 1: A is lying:
A B C
A: Q R not P
B: P R Q
C: not P Q not Q
Statement of B and C contradicts. hence not valid case
Case 2: B is lying:
A B C
A: not Q not R P
B: not P not R not Q
C: not P Q not Q
Valid case A= R ; B = Q; C = P
Case 3: C is lying:
A B C
A: not Q not R P
B: P R Q
C: P not Q Q
A and B are contradicting about B. Not valid case
Hence case 2 is valid only
And A= R ; B = Q; C = P
|
|
Q.No. :
|
20
|
Question :
|
|
A:
|
B
|
B:
|
C
|
C:
|
A
|
D:
|
Either
B or A
|
Answer: A
|
|
|
The
three questions are based on the information given below:-
In a Vintage Car rally five cars- Cadillac, Chevrolet, Toyota, Ambassador
and Fiat are ranked in decreasing order of elegance, maintenance and age.
The oldest is ranked 1st and the youngest is ranked 5th
and so on.
1). Toyota is not the best maintained.
2). The most elegant cat s ranked 4th in maintenance and 2nd
in age.
3). The best maintained car is the 3rd in elegance and the
youngest.
4). The car which is 3rd in maintenance is ranked 5th
in elegance and 1st in age.
5). Ambassador and Fiat are ranked 2nd and 3rd in
ages respectively.
6). Chevrolet is not the least elegant one.
7). The second most elegant car s ranked last in maintenance and it is
Cadillac.
8). No two cars have the same rank n any two categories.
|
Q.No. :
|
21
|
Question :
|
What is the rank of Fiat in the
category of elegance?
Report
| Discuss
|
A (Your Answer):
|
1
|
B:
|
2
|
C:
|
3
|
D:
|
4
|
Answer: D
|
|
|
Q.No. :
|
22
|
Question :
|
|
A:
|
Fiat
|
B:
|
Ambassador
|
C:
|
Chevrolet
|
D:
|
Toyota
|
Answer: B
|
|
|
Q.No. :
|
23
|
Question :
|
Which of the following shows the
rank of Toyota in the order of age, maintenance and elegance?
Report
| Discuss
|
A:
|
5,
1, 3
|
B:
|
3,
2, 4
|
C:
|
1,
3, 5
|
D:
|
1,
2, 3
|
Answer: C
|
|
|
Q.No. :
|
24
|
Question :
|
How is the man I met today, who
is the brother of my grandfather's only son-in-law related to me, if I do
not have a paternal aunt?
Report
| Discuss
|
A:
|
Father
|
B:
|
Maternal
uncle
|
C:
|
Paternal
uncle
|
D (Your Answer):
|
Cousin
|
Answer: C
|
|
|
Here grandfather refers to
mother's father as there is no parental aunt.
So grandfather daughter's husband will be your father.
And brother of your father is your parental uncle
|
|
Q.No. :
|
25
|
Question :
|
When I arrived at the theatre,
Vinay was already there but Vijay was not there. Prabhat came after me and
exactly one of the Prabhat and Prakash was there at the theatre when I
arrived and exactly one person arrived between their arrivals. Who arrived
last?
Report
| Discuss
|
A:
|
Prabhat
|
B (Your Answer):
|
Prakash
|
C:
|
Vinay
|
D:
|
Vijay
|
Answer: D
|
|
|
The correct order of arrival is:
Vinay, Prakash, me, Prabhat, Vijay
When I reached there Vijay was not there but Vinay was. So Vinay came
before me.
Prabhat came after me and exactly one of the Prabhat and Prakash was there
at the theatre when I arrived. So the order of arrival of the three was:
Prakash, me, Prabha.
And Vijay didn't come before me.
So the order is: Vinay, Prakash, me, Prabhat, Vijay
Vijay is the last person to arrive.
|
|
Q.No. :
|
26
|
Question :
|
The surface area of a sphere is
400 m2. This sphere is then cut in to two halves. Find the total
surface area of one of the halves.
Report
| Discuss
|
A (Your Answer):
|
200
m2
|
B:
|
300
m2
|
C:
|
400
m2
|
D:
|
350
m2
|
Answer: B
|
|
|
Q.No. :
|
27
|
Question :
|
What should be the length of the
cloth in meters, required to make a right circular conical tent. Even the
width of the cloth is 5 m. Also, the radius of the tent is 7 m and its
height is 24 m.
Report
| Discuss
|
A:
|
110
m
|
B (Your Answer):
|
220
m
|
C:
|
165
m
|
D:
|
330
m
|
Answer: A
|
|
|
Q.No. :
|
28
|
Question :
|
A right circular cone of radius
'a' has the same volume as that of right circular cylinder with base radius
'r'. Find the ratio of the heights of the cone and cylinder.
Report
| Discuss
|
A (Your Answer):
|
r2/a2
|
B:
|
2r2/a2
|
C:
|
3r2/a2
|
D:
|
4r2/a2
|
Answer: C
|
|
|
Q.No. :
|
29
|
Question :
|
A road that is 14 m wide
surrounds a circular path of whose circumference is 132 m. What will be the
area of road?
Report
| Discuss
|
A:
|
2462
m2
|
B (Your Answer):
|
2464
m2
|
C:
|
2468
m2
|
D:
|
2470
m2
|
Answer: B
|
|
|
Let radius of the circular path
be r
So, 2π r = 132
or, 2 * 22/7 * r =132
or r = 21
Radius of circular Path including road = 21 + 14 = 35
So, area of the road = π(352 - 212) = 2464
|
|
Q.No. :
|
30
|
Question :
|
The remainder obtained when a
prime number greater than 8 is divided by 8 is r. What can be said about r?
I. r is always odd
II. r is always prime.
III. r is either 1 or prime.
Report
| Discuss
|
A:
|
I
only
|
B (Your Answer):
|
II
only
|
C:
|
I
and II only
|
D:
|
I
and III only
|
Answer: D
|
|
|
Q.No. :
|
31
|
Question :
|
By selling 5 dozen mangoes for
Rs 156 it was found that 3/10 th of the outlay was gained. What should the
retail price per mango be in order to gain 60%?
Report
| Discuss
|
A:
|
Rs
4
|
B (Your Answer):
|
Rs
2
|
C:
|
Rs
3.2
|
D:
|
Rs
4.2
|
Answer: C
|
|
|
Let Cost price of mangoes is Rs
x.
According to question
Selling price of one mango = 156/60
Now
x*(1+3/10)=156/60
x=2
Now retail price per mango be in order to gain 60%= 2*(1+60/100)
=3.2
|
|
Q.No. :
|
32
|
Question :
|
A shopkeeper sells a microwave at
a discount on its marked price of Rs 2500. But n a clearance sale he gives
an additional discount of 20% thus selling it at Rs 1500. Find the first
discount.
Report
| Discuss
|
A (Your Answer):
|
20%
|
B:
|
25%
|
C:
|
12%
|
D:
|
30%
|
Answer: B
|
|
|
Q.No. :
|
33
|
Question :
|
A father is 50 years old and his
son is 22 years old. In how many years will the father be twice as old as
his son?
Report
| Discuss
|
A:
|
8
|
B:
|
10
|
C:
|
6
|
D (Your Answer):
|
12
|
Answer: C
|
|
|
Q.No. :
|
34
|
Question :
|
The sum of the present ages of
Sujith and Leela is 47 years. Ten year ago, Sujith's age was 13 times the
difference in their present ages. Find the Leela's present age?
Report
| Discuss
|
A:
|
23
years
|
B:
|
24
years
|
C (Your Answer):
|
25
years
|
D:
|
26
years
|
Answer: B
|
|
|
Let present age of Sujith = x
present age of Leela = y
According to question,
x + y = 47
x - 10 = 13 | x - y | , where | | is modulus
either x-10 = 13(x - y) or, x-10 = 13(y-x)
or 47-y-10=13(47-2y) ; 37-y -10= 13(y- 47+y)
or 37 - y = 611 - 26y ; 37 - y = 26y - 611
or 25y = 574 ; 27y = 648
or y = 574/25 ; y = 24
So, y = 24
and x = 47-24 = 23
Hence Age of Leela = y = 24 Ans
|
|
Q.No. :
|
35
|
Question :
|
In an examination, there are
five subjects and each has the same maximum. A boy's marks are in the ratio
3:4:5:6:7 and his aggregate is 3/5 th of the full marks. In how many
subjects dd he get more than 50% marks?
Report
| Discuss
|
A (Your Answer):
|
1
|
B:
|
2
|
C:
|
3
|
D:
|
4
|
Answer: C
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