Aptitude solved question's of various company

Q.No. : 1 Question : Sameer can do a piece of work in 9hours. Rahul can do the same piece of work in 8hours. Their boss asks them to work along with Ronak and hence they finish the work in 3 hours. If their boss offers them Rs. 7200 for the work, how much does Ronak earn? Report | Discuss A: Rs 6900 B (Your Answer): Rs 5000 C: Rs 4200 D: Rs 2100 Answer: D Solution Part of the work done by ronak = 1/3-(1/8 + 1/9) 1/x = 7/72 Amount that ronak gets = 7200(7/72)* 3= Rs 2100.

Q.No. : 2 Question : Abhishek was given a piece of work to be done in 24 days. The lazy person that he was, he works at 75%, 50%, 80% and 25% of his usual rate on 1st, 2nd, 3rdand 4th days respectively. In how many days will he finish the remaning jo. If he works at his usual rate from the 5th day? Report | Discuss A: 21.7 B (Your Answer): 24 C: 25 D: 26.5 Answer: A Solution At his usual pace Abhishek can do 1/24 of the work in one day. Work done on the first day = (3/4)(1/24)=1/32 second day= 1/48 third day = 1/30 fourth day = 1/96. Work left = 1-[1/32+1/48+1/30+1/96] = 217/240 Time taken to complete remaining work= (217/240)* 24 = 21.7 days

Q.No. : 3 Question : An empty conical water container is placed on its base and water is poured into it through the vertex. It takes 20 minutes for the water level to rise to 40% of the height of the cone. How long will it take for the water level to rise to 70% of the height of the cone? Report | Discuss A (Your Answer): 22.8 minutes B: 24.8 minutes C: 35 minutes D: 40 minutes Answer: B Solution When water level rise upto 40 %. Vol of water =1/3 πR2H-1/3πr2h h = H-H*40/100 = 3/5H r = 3/5R ( from triangle law of geometry) So vol of water poured in 20 min = 1/3 π[R2H-(3/5R)2(3/5H)] = 1/3 π[98/125R2H] Now to raise the water to 70 % h1 = H-H*70/100 = 3/10H r1 = 3/10R Vol of water will be = 1/3 π[R2H-(3/10R)2(3/10H)] = 1/3 π[973/1000R2H] Required time =( 973/1000)*(20)/(98/125) = 24.8 min Ans

Q.No. : 4 Question : Two alloy A and B contains copper and zinc in the ratio 5:11 and 3:5 respectively. If equal weights of the two alloy are melted together to form a third alloy, find the ratio of the weights of copper and zinc in the third alloy. Report | Discuss A (Your Answer): 11:21 B: 9:19 C: 21:11 D: 19:9 Answer: A

Q.No. : 5 Question : There are two classes A and B. The average weight of the students in class A is 40 kg. The average weight of the students in class B is 60kg. A student, whose weight is xkg left A and joined B. As a result, the average weight of A, as well as that of decreased, which of the following must be true? Report | Discuss A: 35 < x <= 40 B: 40 < x <60 C (Your Answer): 60 <= x <65 D: 30 < x <= 35 Answer: B

Q.No. : 6 Question : Vipin plays a game wherein he tosses a coin and scores 7 points if head comes up and 8 points for a tail. If an exact total 167 points is required to win the game, then in how much ways can Vipin win? Report | Discuss A: 2 B: 3 C (Your Answer): 4 D: 5 Answer: B Solution Let head and tail occur x and y times respectively. So, for Vipin to win, 7x + 8y = 167 Possible value of x and y is x=1, y=20 x=9, y=13 x=17, y=6 Total number of ways = 3

Q.No. : 7 Question : If 60a=3, 60b=5 then 12[1-a-b]/[2(1-b)] = ? Report | Discuss A: 1 B (Your Answer): 2 C: 3 D: Root(5) Answer: B Solution 60a=3 So, a = log603 60b=5 So, b = log605 Now, Let Y = 12[1-a-b]/[2(1-b)] Taking log with base 60 on both sides, log60Y=log6012[1-a-b]/[2(1-b)] Or, log60Y=[1-a-b]/[2(1-b)] log6012 (1-a-b)/2(1-b) = (1- log603 - log605)/2(1 - log605) = ( log6060 - log603 - log605)/2(log6060 - log605) = [log60(60/15)]/2[log60(60/5)] = log604/2log6012 log60Y = (log604/2log6012)* log6012 = 1/2log604 =log602 So, Y = 2 Ans

Q.No. : 8 Question : In a race of length D m , A beats B by X m and C by Y m. By what distance does B beat C in the same race? Report | Discuss A: (Y-X)D / (D-Y) m B (Your Answer): (Y-X)D / (D-X) m C: (D-Y)D / (D-X) m D: (D-X)D / (D-Y) m Answer: B Solution Suppose time taken by A, B and C to finish the race are t1, t2, t3 respectively. So Speed of A, B and C are D/t1, D/t2 and D/t3 Now When A finishes the race distance travelled by B = Dt2/t1 and distance travelled by C = Dt3/t1 According to question, D-Dt2/t1 = X ............(i) and D-Dt3/t1 = Y ............(ii) We have to find D-Dt3/t2 from (i) t2/t1 = (D-X)/D ..... (iii) from (ii) t3/t1 = (D-Y)/D ..... (iv) From (iii) and (i) we get t3/t2 = (D-Y)/(D-X) So, D-Dt3/t2 = D[(1-(D-Y)/(D-X)] = D(Y-X)/(D-X) Hence B

Q.No. : 9 Question : A and B are two stations. Train P started from A towards B at 6:00 a.m at 90 kmph. At the same time, train Q started from C, an intermediate station 60 km from A, and travelled towards B at 60 kmph, Train R started from B towards A at 7:00 a.m at 120 kmph. All the trains crossed each other simultaneously. Find AB(in km). Report | Discuss A (Your Answer): 390 B: 360 C: 330 D: 300 Answer: D

Q.No. : 10 Question : A, B, C are running around a circular park. They start at the same point. A overtakes C, 3 times for every round that C makes. C overtakes B, 6 times for every round that B makes. What is the ratio of A's speed to that of B? Report | Discuss A: 9:2 B: 18:1 C (Your Answer): 28:1 D: 21:1 Answer: C Solution As A overtakes C three times , A's speed must be four times of C and C speed is 7 times more than B A=4C B=C/7 therefore A/B=28:1

Q.No. : 11 Question : There are 4 identical oranges, 3 identical mangoes and 2 identical apples in the basket. the number of ways in which we can select one or more fruits from the basket is Report | Discuss A: 60 B: 59 C (Your Answer): 57 D: 56 Answer: B Solution There are 4 oranges, 3 mangoes and 2 apples. From 4 oranges we can select either no orange or 1 oranges or 2 or 3 or all 4 oranges. So No of ways of chosing = 5 Similarly we can chose 0, 1, 2 or 3 mangoes out of 3 mangoes. and we can chose 0, 1 or all 2 apples out of 2 apples. So total number of ways of selecting fruit = 5*4*3 = 60 But we have to exclude on case in which no fruit is chosen Hence required answer = 60 - 1 = 59

Q.No. : 12 Question : P is an integer whose digits are zeroes and ones. The sum of the digits of P is 4 and 105< P <107. How many values P can take? Report | Discuss A: 60 B (Your Answer): 10 C: 20 D: 30 Answer: D

Q.No. : 13 Question : A question paper consists of 5 problems, each problem having 3 internal choices. In how many ways can a candidate attempt one or more problems? Report | Discuss A (Your Answer): 63 B: 511 C: 1023 D: 31 Answer: C Solution There are 5 problems. Each problem having three choices to answer. (Suppose the question as a multiple choice question having 3 options) So a candidate can either answer 1, 2, 3, 4 or all 5 questions. No of ways to answer only one question = 5C1*3 No of ways to answer 2 questions = 5C2*32 (For each question there are 3 different choices to answer) No of ways to answer 3 questions = 5C3*33 No of ways to answer 4 questions = 5C4*34 No of ways to answer 5 questions = 5C5*35 So, Total number of ways = 5C1*3 + 5C2*32 + 5C3*33 + 5C4*34 + 5C5*35 = (1+3)5 - 1(From binomial theorem) =1023

Q.No. : 14 Question : Three men shot the same target. The probability of the first, second and the third man hitting the target respectively is 0.3, 0.5 and 0.6. Find the probability that exactly one of them hits the target. Report | Discuss A: 0.41 B (Your Answer): 0.6 C: 0.5 D: 0.7 Answer: A

Q.No. : 15 Question : There are 3 urns containing 3 white and 4 green balls; 2 white and 4 green balls; 1 white and 1 green ball. One urn is chosen at random and a ball is drawn from it. What is the probability that it is a green ball? Report | Discuss A: 43/126 B: 4/21 C: 7/12 D (Your Answer): 73/126 Answer: D

Q.No. : 16 Question : Find the next element in the series given below :- 7, 25, 61, 121, ___ Report | Discuss A (Your Answer): 181 B: 201 C: 211 D: 251 Answer: C Solution Series is :-23-1, 33-2, 43-3, 53-4, ........

Q.No. : 17 Question : P,Q,R,S,T and U are six players from whom two captains X and Y wish to form two teams of 3 players each. P and Q must be in different teams. S and T must be in the same team. If X has P and U in his team, then Y must have taken a team of Report | Discuss A: Q,S,T B (Your Answer): P,S,T C: R,S,T D: P,R,T Answer: A

Q.No. : 18 Question : A message can be sent from one transmitter to another among 9 transmitters A,B,C,D,E,F,G,H and , as shown below. From A to B, from B to C, from C to D, from B to E, from D to H, from E to F, from E to H, from G to H, from F to G, from H to I, from G to I and from D to I. In how many ways can a message be sent from A to I? Report | Discuss A: 7 B (Your Answer): 6 C: 5 D: 4 Answer: C

The following two questions are based on the information given below:- The following is the conversation between A, B and C each of whom has different surname among P, Q and R. One of them is lying and two are telling truth. A :- I am not a Q. C is a P. B is not a R. B:- I am a R. A is a P. C is a Q. C:- I am not Q. A is not a P. B is a Q. Q.No. : 19 Question : Who is R? Report | Discuss A (Your Answer): A B: C C: B D: Either A or B Answer: A Solution Consider all 3 cases: Case 1: A is lying: A B C A: Q R not P B: P R Q C: not P Q not Q Statement of B and C contradicts. hence not valid case Case 2: B is lying: A B C A: not Q not R P B: not P not R not Q C: not P Q not Q Valid case A= R ; B = Q; C = P Case 3: C is lying: A B C A: not Q not R P B: P R Q C: P not Q Q A and B are contradicting about B. Not valid case Hence case 2 is valid only And A= R ; B = Q; C = P

Q.No. : 20 Question : Who is a Q? Report | Discuss A: B B: C C: A D: Either B or A Answer: A

The three questions are based on the information given below:- In a Vintage Car rally five cars- Cadillac, Chevrolet, Toyota, Ambassador and Fiat are ranked in decreasing order of elegance, maintenance and age. The oldest is ranked 1st and the youngest is ranked 5th and so on. 1). Toyota is not the best maintained. 2). The most elegant cat s ranked 4th in maintenance and 2nd in age. 3). The best maintained car is the 3rd in elegance and the youngest. 4). The car which is 3rd in maintenance is ranked 5th in elegance and 1st in age. 5). Ambassador and Fiat are ranked 2nd and 3rd in ages respectively. 6). Chevrolet is not the least elegant one. 7). The second most elegant car s ranked last in maintenance and it is Cadillac. 8). No two cars have the same rank n any two categories. Q.No. : 21 Question : What is the rank of Fiat in the category of elegance? Report | Discuss A (Your Answer): 1 B: 2 C: 3 D: 4 Answer: D

Q.No. : 22 Question : Which of the following is the most elegant car? Report | Discuss A: Fiat B: Ambassador C: Chevrolet D: Toyota Answer: B

Q.No. : 23 Question : Which of the following shows the rank of Toyota in the order of age, maintenance and elegance? Report | Discuss A: 5, 1, 3 B: 3, 2, 4 C: 1, 3, 5 D: 1, 2, 3 Answer: C

Q.No. : 24 Question : How is the man I met today, who is the brother of my grandfather's only son-in-law related to me, if I do not have a paternal aunt? Report | Discuss A: Father B: Maternal uncle C: Paternal uncle D (Your Answer): Cousin Answer: C Solution Here grandfather refers to mother's father as there is no parental aunt. So grandfather daughter's husband will be your father. And brother of your father is your parental uncle

Q.No. : 25 Question : When I arrived at the theatre, Vinay was already there but Vijay was not there. Prabhat came after me and exactly one of the Prabhat and Prakash was there at the theatre when I arrived and exactly one person arrived between their arrivals. Who arrived last? Report | Discuss A: Prabhat B (Your Answer): Prakash C: Vinay D: Vijay Answer: D Solution The correct order of arrival is: Vinay, Prakash, me, Prabhat, Vijay When I reached there Vijay was not there but Vinay was. So Vinay came before me. Prabhat came after me and exactly one of the Prabhat and Prakash was there at the theatre when I arrived. So the order of arrival of the three was: Prakash, me, Prabha. And Vijay didn't come before me. So the order is: Vinay, Prakash, me, Prabhat, Vijay Vijay is the last person to arrive.

Q.No. : 26 Question : The surface area of a sphere is 400 m2. This sphere is then cut in to two halves. Find the total surface area of one of the halves. Report | Discuss A (Your Answer): 200 m2 B: 300 m2 C: 400 m2 D: 350 m2 Answer: B

Q.No. : 27 Question : What should be the length of the cloth in meters, required to make a right circular conical tent. Even the width of the cloth is 5 m. Also, the radius of the tent is 7 m and its height is 24 m. Report | Discuss A: 110 m B (Your Answer): 220 m C: 165 m D: 330 m Answer: A

Q.No. : 28 Question : A right circular cone of radius 'a' has the same volume as that of right circular cylinder with base radius 'r'. Find the ratio of the heights of the cone and cylinder. Report | Discuss A (Your Answer): r2/a2 B: 2r2/a2 C: 3r2/a2 D: 4r2/a2 Answer: C

Q.No. : 29 Question : A road that is 14 m wide surrounds a circular path of whose circumference is 132 m. What will be the area of road? Report | Discuss A: 2462 m2 B (Your Answer): 2464 m2 C: 2468 m2 D: 2470 m2 Answer: B Solution Let radius of the circular path be r So, 2π r = 132 or, 2 * 22/7 * r =132 or r = 21 Radius of circular Path including road = 21 + 14 = 35 So, area of the road = π(352 - 212) = 2464

Q.No. : 30 Question : The remainder obtained when a prime number greater than 8 is divided by 8 is r. What can be said about r? I. r is always odd II. r is always prime. III. r is either 1 or prime. Report | Discuss A: I only B (Your Answer): II only C: I and II only D: I and III only Answer: D

Q.No. : 31 Question : By selling 5 dozen mangoes for Rs 156 it was found that 3/10 th of the outlay was gained. What should the retail price per mango be in order to gain 60%? Report | Discuss A: Rs 4 B (Your Answer): Rs 2 C: Rs 3.2 D: Rs 4.2 Answer: C Solution Let Cost price of mangoes is Rs x. According to question Selling price of one mango = 156/60 Now x*(1+3/10)=156/60 x=2 Now retail price per mango be in order to gain 60%= 2*(1+60/100) =3.2

Q.No. : 32 Question : A shopkeeper sells a microwave at a discount on its marked price of Rs 2500. But n a clearance sale he gives an additional discount of 20% thus selling it at Rs 1500. Find the first discount. Report | Discuss A (Your Answer): 20% B: 25% C: 12% D: 30% Answer: B

Q.No. : 33 Question : A father is 50 years old and his son is 22 years old. In how many years will the father be twice as old as his son? Report | Discuss A: 8 B: 10 C: 6 D (Your Answer): 12 Answer: C

Q.No. : 34 Question : The sum of the present ages of Sujith and Leela is 47 years. Ten year ago, Sujith's age was 13 times the difference in their present ages. Find the Leela's present age? Report | Discuss A: 23 years B: 24 years C (Your Answer): 25 years D: 26 years Answer: B Solution Let present age of Sujith = x present age of Leela = y According to question, x + y = 47 x - 10 = 13 | x - y | , where | | is modulus either x-10 = 13(x - y) or, x-10 = 13(y-x) or 47-y-10=13(47-2y) ; 37-y -10= 13(y- 47+y) or 37 - y = 611 - 26y ; 37 - y = 26y - 611 or 25y = 574 ; 27y = 648 or y = 574/25 ; y = 24 So, y = 24 and x = 47-24 = 23 Hence Age of Leela = y = 24 Ans

Q.No. : 35 Question : In an examination, there are five subjects and each has the same maximum. A boy's marks are in the ratio 3:4:5:6:7 and his aggregate is 3/5 th of the full marks. In how many subjects dd he get more than 50% marks? Report | Discuss A (Your Answer): 1 B: 2 C: 3 D: 4 Answer: C